Question

i use this code to views.py file

@login_required
def login_edit_page(request):
#bla bla
return render_to_response('login_edit_page.html', variables)

the problem is that when the return is called, i have to also pass an argument from the URL. for example the URL is /edit?id=1 in this example i want to pass the id. how can i do that?

this is the full code

@login_required
def login_edit_page(request):
    if request.method == 'POST':
        form = LoginEditForm(request.POST)
        if form.is_valid():
            login1 = _login_edit(request, form, request.GET['id'])
            return HttpResponseRedirect(
                                        '/user/%s/' % request.user.username
                                        )
    id2 = request.GET['id']
    name=''
    url=''
    Login_username =''
    notes= ''
    password=''
    try:
        login1 = login.objects.get(
                                   id = id2,
                                   username=request.user
                                  )
        name = login1.name
        url = login1.loginUrl
        Login_username = login1.login_username
        notes = login1.notes
        password = login1.password
    except (login.DoesNotExist):
        pass
    form = LoginEditForm({
                          'name': name,
                          'url': url,
                          'Login_username': Login_username,
                          'notes': notes,
                          'password': password
                        })
    variables = RequestContext(request, {
                                        'form': form
                                        })
    login1 = _login_edit(request, form, id2)
    return render_to_response('login_edit_page.html', variables)

Answer 1

You can not use render_to_response the way you do. Try this:

...
id2 = request.GET.get('id', None)
...
ctx = {
    'form': form,
    'id': id2
}
return render_to_response('login_edit_page.html', ctx,
                          context_instance=RequestContext(request))

Note, that I added id2 to context dict, so it is reachable in the template by {{ id }}. Also, checkout how I retrieve url parameter from request.

Another approach is to reach url parameter directly from request (as Mark Lavin noticed, it will work in case of django.core.context_processors.request is present in TEMPLATE_CONTEXT_PROCESSORS):

{{ request.GET.id }}

But sincerely, you should make your view more clean, there are a lot of problems in it.