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Home/ Questions/Q 568103
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T13:09:13+00:00 2026-05-13T13:09:13+00:00

I use this method for inserting a textbox in a tablecell protected void EditAttivitaClick(object

  • 0

I use this method for inserting a textbox in a tablecell

protected void EditAttivitaClick(object sender, EventArgs e)
    {
        string attivitaID = ((ImageButton)sender).ID.Split('_')[2];
        tableCell =(HtmlTableCell)FindControl("AttivitaDescrizione_" + attivitaID);                
        TextBox txt = new TextBox();
        txt.Text = tableCell.InnerHtml;
        txt.ID = "TxtAttivitaDescrizione_" + attivitaID;
        tableCell.InnerHtml = "";

    }

It works correctly.
And this function for saving in db the textbox’s value:

protected void SalvaAttivitaClick(object sender, EventArgs e)
    {
        string attivitaID = ((ImageButton)sender).ID.Split('_')[2];
        TextBox txt = (TextBox)FindControl("TxtAttivitaDescrizione_" + attivitaID);
        string a = txt.Text;        
        attivitaTableAdapter.UpdateID(txt.Text, Int32.Parse(attivitaID));
        tableCell.Controls.Clear();
        tableCell.InnerHtml = a;
}

But it doesn’t work. beacuse it doesn’t find the textbox created previously.

I’ve put also EnableViewState=”true” in the file aspx.

Why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T13:09:14+00:00Added an answer on May 13, 2026 at 1:09 pm

    You need to create the textbox every time the page is reloaded, this includes the post back.

    See the asp.net page lifecycle for more information – you should create your dynamic controls in the Page.Init event, so it will be available later on.

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