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Editorial Team
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Asked: 2026-05-30T06:20:12+00:00

I use tomcat server, and try to call a java class from servlet, that

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I use tomcat server, and try to call a java class from servlet, that class has method which will return system current directory path. It’s result is difference with the one when I run form main method in that class.

  • from main method: “D:\Projects\Eclipse\Assignment” (which is where i place my project)
  • from servlet: “D:\IDE\eclipse helios” ( which is where i place my eclipse)

With this I have trouble to access my xml file in my project folder( file not found exception when I call a class from servlet). I want the same result when call from servlet as when run main method. How can I do that?

I would appreciate any advice you could give me to, or any articles that you could recommend.

Thank you.

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1 Answer

  1. Editorial Team

    Why are you trying to access your resources from the filesystem? The expected method of accessing resources from any JAR, including webapps, is using getResourceAsStream:

    http://docs.oracle.com/javase/6/docs/api/java/lang/Class.html#getResourceAsStream(java.lang.String)

    i.e. add the folder containing your resource to the build path, and use YourClassName.class.getResourceAsStream("/foo.xml") to access it.

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