Question

I use VS 2008, .net 3.5 for generate page html using XSLT.

I have Message, that contains \r\n (newlines)

I use this in XSL file:

<b>Message: </b><xsl:value-of select="Message"/><br/>

I need replace \r\n by <br/> in xsl. I have seen several references but not get solution for my issue:

I use this code C# before I call to transform XSLT, but not right:

 m = m.Replace(@"\r\n", "
");
            m = m.Replace(@"\n", "
");
            //m = System.Web.HttpUtility.HtmlDecode(m);

            m = m.Replace(@"\r\n", "<br/>");
            m = m.Replace(@"\n", "<br/>");
            msg = "<Exception>"
            + "<Description>" + d + "</Description>"
            + "<Message>" + m + "</Message>"
            + "<DateTime>" + localTimeString + "</DateTime>"
            + "</Exception>";

I use this references, but not solution

Interpreting newlines with xsl:text?

XSLT Replace function not found

The replace function is only available in XSLT version 2.0, not in version 1.0 which is what Visual Studio uses. Just because you’ve specified version=”2.0″ doesn’t mean that Visual Studio supports it.

I use this like the last reference, but I get error:

 <xsl:call-template name="string-replace-all">
      <xsl:with-param name="text" select="Message"/>
      <xsl:with-param name="replace" select="\r\n"/>
      <xsl:with-param name="by" select="&lt;br/&gt;"/>
 </xsl:call-template>

suggestions, any sample code works ?

Answer 1

The call template above looks OK, you just need the template to go with it!

<!-- XSL FILE -->


<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        version="1.0">
  <xsl:variable name="_crlf"><xsl:text>
</xsl:text></xsl:variable>
  <xsl:variable name="crlf" select="string($_crlf)"/>
  <xsl:template match="/">

    <xsl:for-each select="//demo">
      Demo:
      <xsl:call-template name="crlf-replace">
    <xsl:with-param name="subject" select="./text()"/>
      </xsl:call-template>
    </xsl:for-each>
  </xsl:template>

  <xsl:template name="crlf-replace">
    <xsl:param name="subject"/>

    <xsl:choose>
      <xsl:when test="contains($subject, $crlf)">
    <xsl:value-of select="substring-before($subject, $crlf)"/><br/>
    <xsl:call-template name="crlf-replace">
      <xsl:with-param name="subject" select="substring-after($subject, $crlf)"/>
    </xsl:call-template>
      </xsl:when>
      <xsl:otherwise>
    <xsl:value-of select="$subject"/>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>

</xsl:stylesheet>


<!-- XML FILE -->

<?xml version="1.0"?>

<demos>
  <demo>xslt is really fun</demo>
  <demo>you quite often use recursion in xslt</demo>
  <demo>so there!</demo>
</demos>