Question

I use window.onerror(message,url,line) to log my error messages because it gives me more debug information than try{}catch(e){}.

However, consider the following:

function1(); // Generates error
function2(); // Will not be executed

How can I ensure that function2 will fire while still using window.onerror?

Answer 1

In the meantime, I’ve found a way using setTimeout, but I hope there might be a better way:

setTimeout(function1);
setTimeout(function2);    

See http://jsfiddle.net/7y2Ej/1/