Question

I used a generator to create s

s= generator(n)

the generator yeilds (a,b) for n in a range(n). where a=[w,x] and b=[y,z]

printing s using

for i in s:
    print i

this returns:

([0.27704232355167768, 0.44459304959240675], [0.4387731877846518, 0.38108111684466683])
([0.27704232355167768, 0.44459304959240675], [0.6362447250743466, 0.72047209074359853])
([0.27704232355167768, 0.44459304959240675], [0.65419386891877318, 0.025362727486327286])
([0.27704232355167768, 0.44459304959240675], [0.039966264334369672, 0.9662795347591735])

However I would like

0.27704232355167768 0.44459304959240675 0.4387731877846518 0.38108111684466683
0.27704232355167768 0.44459304959240675 0.6362447250743466 0.72047209074359853
0.27704232355167768 0.44459304959240675 0.65419386891877318 0.025362727486327286
0.27704232355167768 0.44459304959240675 0.039966264334369672 0.9662795347591735

I have tried many variations of the idea below

print '\n'.join('\t'.join(x) for x in s)

but to n0 avail and tend to return the s in the same format. Can anyone help me around this issue?

Answer 1

from itertools import chain
'\n'.join('\t'.join(map(str,tuple(chain(*i)))) for i in s)

chain flattens each row, so you can just join all of the elements with a tab, then join rows with newline.