Question

I Used Chain as in :

in views.py

places_list = Place.objects.all().order_by('-datetimecreated')[:5]
events_list = Event.objects.all().order_by('-datetimecreated')[:5]
photos_list = Photo.objects.all().order_by('-datetimecreated')[:5]
result_list = list(chain(photos_list, places_list, events_list))

In template file

    {% for item in result_list %}

        <a href="{% url view_place item.slug %}">{{item.title}}</a>

    {% endfor %}

that’s to display a place but how to display an event or photo ?

        <a href="{% url view_event item.slug %}">{{item.title}}</a>
        <a href="{% url view_photo item.slug %}">{{item.caption}}</a>

thanks in advance .

Answer 1

I need to know a bit more to answer your question properly, but here are some ideas that might help you. I’m making the assumption that photos_list, places_list and events_list are all objects of different classes that are Django models.

Option 1: Define a method on each class that determines the type of the object

For example, define a content_type method on each model, like this:

class Photo(models.Model):
    def type(self):
        return 'photo'

And then check this in your template:

{% for item in result_list %}
    {% if item.type == "photo" %}
        ...
    {% elif item.type == "place" %}
        ...
    {% else %}
        ...
    {% end %}
{% endfor %}

Option 2: Define a render method on each class

This is probably much uglier, but you could define a render method on each object that returns the complete HTML you want to spit out for that object. Then it’s a case of doing this in your template:

{% for item in result_list %}
    {{ item.render }}
{% endfor %}

Sidenote: Consider inheritance

It sounds like photos, places and events are all things that could appear in the same feed, and as such they might share some common fields (like posted_at). There are various things you need to consider with regard to this, so it’s probably best to look at the Django documentation on model inheritance.