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Home/ Questions/Q 7712121
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T01:32:56+00:00 2026-06-01T01:32:56+00:00

I used private BitmapImage byteArrayToImage(byte[] byteArrayIn) { try { MemoryStream stream = new MemoryStream();

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I used

private BitmapImage byteArrayToImage(byte[] byteArrayIn)
{
    try
    {               
        MemoryStream stream = new MemoryStream();
        stream.Write(byteArrayIn, 0, byteArrayIn.Length);
        stream.Position = 0;
        System.Drawing.Image img = System.Drawing.Image.FromStream(stream);
        BitmapImage returnImage = new BitmapImage();
        returnImage.BeginInit();
        MemoryStream ms = new MemoryStream();
        img.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp);
        ms.Seek(0, SeekOrigin.Begin);
        returnImage.StreamSource = ms;
        returnImage.EndInit();

        return returnImage;
    }
    catch (Exception ex)
    {
        throw ex;
    }
    return null;
}

This method in my application to convert byte array to an image. But it throws “Parameter is not valid” exception.. why it is happening..? Is there any alternative method.??

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  1. Editorial Team
    Editorial Team
    2026-06-01T01:32:57+00:00Added an answer on June 1, 2026 at 1:32 am

    Hi this should be working:

        private static BitmapImage LoadImage(byte[] imageData)
        {
            if (imageData == null || imageData.Length == 0) return null;
            var image = new BitmapImage();
            using (var mem = new MemoryStream(imageData))
            {
                mem.Position = 0;
                image.BeginInit();
                image.CreateOptions = BitmapCreateOptions.PreservePixelFormat;
                image.CacheOption = BitmapCacheOption.OnLoad;
                image.UriSource = null;
                image.StreamSource = mem;
                image.EndInit();
            }
            image.Freeze();
            return image;
        }
    
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