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Asked: 2026-05-11T03:21:11+00:00

I used the following query to find duplicates: SELECT userID, COUNT(userID) AS NumOccurrences FROM

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I used the following query to find duplicates:

SELECT userID, COUNT(userID) AS NumOccurrences FROM userDepartments GROUP BY userID HAVING ( COUNT(userID) > 1 )

I then tried adding an inner join so I could see the user names that match, which are stored in a different table.

SELECT userDepartments.userID, users.firstname, users.lastname, COUNT(userID) AS NumOccurrences FROM userDepartments INNER JOIN users ON userDepartments.userID = users.userID GROUP BY userID HAVING ( COUNT(userID) > 1 )

But it gave me an error saying that users.firstname was not part of some aggregate function or something…

Does anyone know how I can get the count, only show users with more than 1 department, and also get the first and last name out of the other table so I can get a list of users names who have more than one department assigned?

EDIT: THIS IS THE QUERY THAT ENDED UP WORKING FOR ME…

SELECT     firstname, lastname FROM         tbl_users WHERE     (userID IN                           (SELECT     userID                             FROM          tbl_usersDepts                             GROUP BY userID                             HAVING      (COUNT(userID) > 1)))
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1 Answer

  1. I would rearrange the query a little bit….

    SELECT     duplicates.NumOccurrences,     duplicates.userID,     users.firstname,     users.lastname FROM (     SELECT         userID,         COUNT(userID) AS NumOccurrences     FROM userDepartments     GROUP BY userID     HAVING COUNT(userID) > 1 ) duplicates INNER JOIN users ON duplicates.userID = users.userID
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