Question

I used this below code on my asp.net controller to return Json object on my Ajax on javascript

public JsonResult myMethod()
{
    // return a Json Object, you could define a new class
    return Json(new
    {
        Success = true, //error
        Message = "Success" //return exception
    });
}

Jquery-Ajax:

$.ajax({
    type: "POST",
    url: url_ ,
    data: search,
    success: function(data) {   
        //Show Json Properties from Controller ( If Success == false show exception Message from controller )
        if (data.Success)  
        {
            alert(data.Message); //display success 
        }
        else
        {
            alert(data.Message) //display exception
        }
    },
    error: function(XMLHttpRequest, textStatus, errorThrown) {
        alert("error: " + XMLHttpRequest.responseText);
    },
    dataType: 'json'
});

How can this be done on Web Api Controller?

Can you give me some examples or url as reference.

Thanks and Regards

Answer 1

If you create yourself a new HttpContent class for delivering JSON, like…

 public class JsonContent : HttpContent {

    private readonly MemoryStream _Stream = new MemoryStream();
    public JsonContent(object value) {

        Headers.ContentType = new MediaTypeHeaderValue("application/json");
        var jw = new JsonTextWriter( new StreamWriter(_Stream));
        jw.Formatting = Formatting.Indented;
        var serializer = new JsonSerializer();
        serializer.Serialize(jw, value);
        jw.Flush();
        _Stream.Position = 0;

    }
    protected override Task SerializeToStreamAsync(Stream stream, TransportContext context) {
        return _Stream.CopyToAsync(stream);
    }

    protected override bool TryComputeLength(out long length) {
        length = _Stream.Length;
        return true;
    }
}

Then you can do,

      public HttpResponseMessage Get() {
            return new HttpResponseMessage() {
                Content = new JsonContent(new
                {
                    Success = true, //error
                    Message = "Success" //return exception
                })
            };
        }

just like you do with JsonResult.