Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8194079
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 7, 20262026-06-07T04:41:57+00:00 2026-06-07T04:41:57+00:00

I used to use the >> operator for right shifting. Now I’ve just replaced

  • 0

I used to use the >> operator for right shifting. Now I’ve just replaced it with >>> and found the same result. So I can’t figure out whether these two are fundamentally equal or not.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-07T04:41:59+00:00Added an answer on June 7, 2026 at 4:41 am

    The first operator sign-extends the value, shifting in a copy of the sign bit; the second one always shifts in a zero.

    The reason for this is to emulate unsigned integers for the purpose of doing bit operations, partially compensating for the lack of unsigned integral types in Java.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I used to use an add-on for firefox called measureit. Now its not working
I'm just confused about what's the padding mode used when use crypto:des_ecb_encrypt/2 in erlang.
Does the ?? operator in C# use shortcircuiting when evaluating? var result = myObject
My code reviewers has pointed it out that the use of operator[] of the
I used to use a guitar tab site and it had a feature where
I used to use procedural-style PHP. Later, I used to create some classes. Later,
I used to use SVN 1.4 on OS X Leopard and everything was fine.
I used to use this script for jquery email obfuscation: $(.replaceAt).replaceWith(@); $(.obfuscate).each(function () {
I used to use Backbone.js as an easy MVC framework which have build-in routing
When I used to use IIS 6 (or so) I'd often make a virtual

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.