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Home/ Questions/Q 3680352
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T03:34:00+00:00 2026-05-19T03:34:00+00:00

i using below code to get a picture from URL: URL url=new URL(http://www.google.com/images/logos/ps_logo2.png); InputStream

  • 0

i using below code to get a picture from URL:

    URL url=new URL("http://www.google.com/images/logos/ps_logo2.png");
    InputStream in=url.openStream();
    ByteArrayOutputStream tmpOut = new ByteArrayOutputStream();
    byte[] buf = new byte[512];
    int len;
    while (true) {
        len = in.read(buf);
        if (len == -1) {
            break;
        }
        tmpOut.write(buf, 0, len);
    }
    tmpOut.close();

    byte[] picture=tmpOut.toByteArray();
    System.out.println(picture.length);

this code is okay,but my internet connect is very very bad,

so ,I maybe get a broken picture like this:

alt text

How can I ensure the picture file is complete ?

I think you can add this code to try and test this:

if (len == -1) { change to if (len == -1 || (int)(Math.random()*100)==1 ) {

full test code:

    URL url=new URL("http://www.google.com/images/logos/ps_logo2.png");
    InputStream in=url.openStream();
    ByteArrayOutputStream tmpOut = new ByteArrayOutputStream();
    byte[] buf = new byte[512];
    int len;
    while (true) {
        len = in.read(buf);
        if (len == -1 || (int)(Math.random()*100)==1 ) {
            break;
        }
        tmpOut.write(buf, 0, len);
    }
    tmpOut.close();
    byte[] picture =tmpOut.toByteArray();
    System.out.println(picture.length);

thanks for help 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T03:34:00+00:00Added an answer on May 19, 2026 at 3:34 am

    Have you looked into using the ImageIO class for loading images – it takes care of a lot of these details for you:

    Image image;
    try {    
      URL url = new URL("http://www.google.com/images/logos/ps_logo2.png");
      image = ImageIO.read(url);
    } catch (IOException e) {
       ...
    }
    
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