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Home/ Questions/Q 6626451
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:53:38+00:00 2026-05-25T21:53:38+00:00

I usually only have the definitions of my classes inside a header if they

  • 0

I usually only have the definitions of my classes inside a header if they are template classes.- If this is the case, i still like to split declaration and definition inside the header like that:

template<class T>
class Foo
{
public:

    Foo();

    void fooFunc();
};


template<class T>
Foo<T>::Foo()
{

}

template<class T>
void Foo<T>::fooFunc()
{

}

that code also compiles. But If I remove the template:

class Foo
{
public:

    Foo();

    void fooFunc();
};


Foo::Foo()
{

}

void Foo::fooFunc()
{

}

i get a duplicate symbol error for Foos functions. I was very sure that this should work and am very surprised that it does not. Is this expected behaviour? If I add an inline before the definition it works too.

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:53:39+00:00Added an answer on May 25, 2026 at 9:53 pm

    Yes, it’s expected behavior.

    Inline functions are meant to be compiled separately into each call site so duplication is no problem. For template functions, the compiler flags them in the object file such that the linker will basically ignore duplicates, since it can be difficult to predict where the template will or will not be instantiated.

    But conventional functions are expected to be defined exactly once. If you define one in a header file, it gets compiled into each translation unit that includes the header, leading to a “duplicate symbol” error at link time if you have more than one object file containing a copy of the function.

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