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Home/ Questions/Q 6893973
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T06:43:29+00:00 2026-05-27T06:43:29+00:00

I wanna to multiple 2 numbers,which have got 32bits. I can define DD for

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I wanna to multiple 2 numbers,which have got 32bits.

I can define DD for each variables,but I can’t define DQ variables for result in emu8086.

data_seg segment
    X DD 12341234H
    Y DD 11111111H
    Z DQ ?
    data_seg ends

It will return error in line number 4,which declare Z as DQ .

Can 8086 support DQ and DT type of variables?If it can,where is the problem?
(I’m using emu8086 to emulate my assembly code)

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  1. Editorial Team
    Editorial Team
    2026-05-27T06:43:30+00:00Added an answer on May 27, 2026 at 6:43 am

    Just a guess, but as the 8086 can’t natively handle quadwords or twords (no FPU) perhaps there is no sense in supporting such data sizes.

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