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Home/ Questions/Q 3343230
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T00:55:50+00:00 2026-05-18T00:55:50+00:00

I want a 0 to be considered as an integer and a ‘0’ to

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I want a 0 to be considered as an integer and a ‘0’ to be considered as a string, but empty() considers the ‘0’ as a string in the example below,

$var = '0';

// Evaluates to true because $var is empty
if (empty($var)) {
    echo '$var is empty';
}

How can I ‘make’ empty() to take ‘0’s as strings?

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  1. Editorial Team
    Editorial Team
    2026-05-18T00:55:50+00:00Added an answer on May 18, 2026 at 12:55 am

    You cannot make empty() take it. That is how it was designed. Instead you can write an and statement to test:

    if (empty($var) && $var !== '0') {
        echo $var . ' is empty';
    }
    

    You could use isset, unless of course, you want it to turn away the other empties that empty checks for.

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