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Home/ Questions/Q 7192601
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T19:58:28+00:00 2026-05-28T19:58:28+00:00

I want a pair<A,B>* . make_pair(a,b) will give me a pair<A,B> (note the pair

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I want a pair<A,B>*. make_pair(a,b) will give me a pair<A,B> (note the pair isn’t a pointer). Is there a standard way to make a pair pointer? I tried adding new before after and in between the two words and it doesn’t appear to exist.

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  1. Editorial Team
    Editorial Team
    2026-05-28T19:58:29+00:00Added an answer on May 28, 2026 at 7:58 pm

    There isn’t. You can roll your own:

    template<typename X, typename Y>
    std::pair<typename std::decay<X>::type, typename std::decay<Y>::type>*
    heap_pair(X&& x, Y&& y) {
      typedef typename std::decay<X>::type decayed_X;
      typedef typename std::decay<Y>::type decayed_Y;
      return new std::pair<decayed_X, decayed_Y>(
        std::forward<X>(x),
        std::forward<Y>(y)
      );
    }
    

    But you might want to add allocator customization to it.

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