Question

i want a regex pattern to remove images which src attribute is empty, for example :

$html = '<img src="adasas.jpg" /><br />asasas<br />sdfsdf<br /><img title="asa" src="" />';

or

$html = '<img src="adasas.jpg" /><br />asasas<br />sdfsdf<br /><a href="adafgag"><img title="asa" src="" /></a>';

if this <img exist between <a> tag, i want also remove all ( <a and <img ) .

I Tested below code, but it removed all of $html

echo preg_replace( '!(<a([^>]+)>)?<img(.*?)src=""([^>]+)>(</a>)?!si' , '' , $html );

Can anybody help to me ?

thanks in advance

Answer 1

Your problem is likely that the generic .*? matched too much. Rather use [^>]* like in the other parts of the pattern:

'!(<a\s[^>]+>)?<img([^>]+)src=""([^>]*)>(</a>)?!i'