Question

I want a regular expression in java that must contain at least a alphabet and a number at any position. It is for the password that contain the digits as well as numbers.

This should work for:

“1a1b23nh” Accepted

“bc112w” Accepted

“abc” Not accepted

“123” Not accepted

Special characters are not allowed.

Answer 1

(([a-z]+[0-9]+)+|(([0-9]+[a-z]+)+))[0-9a-z]*

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How about a simple content check? Check if there are number(s) and character(s)

String input = "b45z4d";
boolean alpha = false;
boolean numeric = false;
boolean accepted = true;
for (int i = 0; i < input.length(); ++i)
{
    char c = input.charAt(i);
    if (Character.isDigit(c))
    {
        numeric = true;
    } else if (Character.isLetter(c))
    {
        alpha = true;
    } else
    {
        accepted = false;
        break;
    }
}

if (accepted && alpha && numeric)
{
    // Then it is correct
}