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Home/ Questions/Q 903495
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T15:53:20+00:00 2026-05-15T15:53:20+00:00

I want a regular expression that could be used to find the following lines:

  • 0

I want a regular expression that could be used to find the following lines:

<rect width='10px' height ='20px'/>
<rect width='20px' height ='22px'/>
<circle radius='20px' height ='22px'/>

and replace them by the these lines:

<rect width='10px' height ='20px'></rect>
<rect width='20px' height ='22px'></rect>
<circle radius='20px' height ='22px'></circle>

Thank you .

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T15:53:21+00:00Added an answer on May 15, 2026 at 3:53 pm

    I don’t think regex is the right tool for this job, but something like this will “work” some of the time.

        String text =
            " <rect width='10px' height ='20px'/> \n" +
            " <rect width='20px' height ='22px'/> \n" +
            " <circle radius='20px' height ='22px'/> \n" +
            " <square/> <rectangle></rectangle> \n" +
            " <foo @!(*#&^#@/> <bar (!@*&(*@!#> </whatever>";
        System.out.println(
            text.replaceAll("<([a-z]+)([^>]*)/>", "<$1$2></$1>")
        );
    

    The above Java snippet prints:

     <rect width='10px' height ='20px'></rect> 
     <rect width='20px' height ='22px'></rect> 
     <circle radius='20px' height ='22px'></circle> 
     <square></square> <rectangle></rectangle> 
     <foo @!(*#&^#@></foo> <bar (!@*&(*@!#> </whatever>
    

    The regex is this (see also on rubular.com):

    /<([a-z]+)([^>]*)\/>/
    

    Essentially we try to capture what we hope is a tag name in group 1, and everything else until the /> in group 2, and use these captured strings in our substitution.

    References

    • regular-expressions.info/Grouping
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