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I want an algorithm to simulate this loaded die:
the probabilities are:
1: 1/18
2: 5/18
3: 1/18
4: 5/18
5: 1/18
6: 5/18
It favors even numbers.
My idea is to calculate in matlab the possibility of the above.
I can do it with 1/6 (normal die), but I am having difficulties applying it for a loaded die.
One way: generate two random numbers: first one is from 0 to 5 (0: odd, 1 – 5: even), which is used to determine even or odd. Then generate a second between 0 and 2, which determines exact number within its category. For example, if the first number is 3 (which says even) and second is 2 (which says the third chunk, 1-2 is a chunk, 3-4 is another chunk and 5-6 is the last chunk), the the result is 6.
Another way: generate a random number between 0 and 17, then you can simply / 6 and % 6 and use those two numbers to decide. For example, if /6 gives you 0, then the choice is between 1 and 2, then if % 6 == 0, the choice lands on 1, otherwise lands on 2.