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Home/ Questions/Q 8509627
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T03:29:07+00:00 2026-06-11T03:29:07+00:00

I want an custom link for my paginator. I use the folowing code $this->Paginator->options(array(

  • 0

I want an custom link for my paginator. I use the folowing code

$this->Paginator->options(array(
        'url'=>array(
            "/custom",24,"custom1"
        ),
        'escape'=>false
    )
);

This results in a link with the original controller in front of the link like this:

 /controller/action/%2Fcustom/24/custom1

I want the linkt to be /custom/24/custom1. So without the escaped(/) and as a root.

How can I accomplish this?

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  1. Editorial Team
    Editorial Team
    2026-06-11T03:29:08+00:00Added an answer on June 11, 2026 at 3:29 am

    Did you try

    'url' => '/custom/24/custom1'
    

    ? The syntax that you use is not valid I think. The available formats are:

    'url' => 'action'
    

    or

    'url' => '/controller/action'
    

    or

    'url' => array(
        'controller' => 'your_controller',
        'action' => 'your_action'
    )
    

    See http://book.cakephp.org/1.3/en/view/1387/options-url and http://book.cakephp.org/1.3/view/1448/url.

    If none of these formats satisfies you, you can consider creating a custom route, see http://book.cakephp.org/1.3/view/948/Defining-Routes.

    Cheers

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