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Home/ Questions/Q 8559183
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T15:58:54+00:00 2026-06-11T15:58:54+00:00

I want create a command that has the following structure command path/to/some/file How do

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I want create a command that has the following structure command path/to/some/file

How do I enable this without entering the option -p or –path?

#!/usr/bin/env ruby
require 'optparse'

options = {}
option = OptionParser.new() do |opts|

    opts.on('-p PATH', '--path PATH', 'First path argument') do |path| // How do I enable this without entering the option -p or --path? 
       options[:path] = path
    end
end

option.parse!(ARGV)
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  1. Editorial Team
    Editorial Team
    2026-06-11T15:58:55+00:00Added an answer on June 11, 2026 at 3:58 pm

    It’s not stated very explicitly in the docs, but OptionParser will extract all options from ARGV and leave the rest, so the right way is just to use ARGV as if it were the list of paths.

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