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Home/ Questions/Q 6180895
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T00:55:34+00:00 2026-05-24T00:55:34+00:00

I want create a new <li> component, then add href, class, etc.. and finally

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I want create a new <li> component, then add href, class, etc.. and finally place it in another element.

I thought this would work, but it doesn’t:

var points = [1, 2, 3, 4];

$.each(points , function(){
    var $elm = $('<a>'+'Point:'+$(this)+'</a>');
    $elm.css('point');
    $elm.attr('href','http://somelink');
    $('#points_list').append('<li>'+$elm+'</li>');
});

The html code is:

<ul id="points_list"/>

The output is:

  • Object
  • Object
  • Object
  • Object
    • 1 1 Answer
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    1. Editorial Team
      Editorial Team
      2026-05-24T00:55:34+00:00Added an answer on May 24, 2026 at 12:55 am

      That JavaScript is invalid (the first line is a syntax error). I see you’ve corrected it.

      I think this may be what you mean (I’ve had to guess at the css bit, I assume you meant to add that as a class) (live copy):

      var points = [1, 2, 3, 4];
      
      $.each(points, function(index, point) {
          var anchor, li;
      
          anchor = $('<a>Point:' + point + '</a>');
          anchor.addClass('point');
          anchor.attr('href','http://somelink');
          li = $("<li>");
          li.append(anchor);
          $('#points_list').append(li);
      });
      

      But it can be simpler:

      var points = [1, 2, 3, 4];
      
      $.each(points, function(index, point) {
          $('#points_list').append(
              '<li><a class="point" href="http://somelink">Point:' + point + '</a></li>'
          );
      });
      

      I’d also recommend looking up the points_list once and then reusing the reference:

      var points = [1, 2, 3, 4];
      var list = $('#points_list');
      $.each(points , function(index, point){
          list.append(
              '<li><a class="point" href="http://somelink">Point:' + point + '</a></li>'
          );
      });
      

      …since even looking things up by id is not free.

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