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Home/ Questions/Q 3670354
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T02:21:15+00:00 2026-05-19T02:21:15+00:00

I want do a GetUsersInRoles, i.e. I want to find all MembershipUser’s having at

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I want do a “GetUsersInRoles”, i.e. I want to find all MembershipUser’s having at least one of the roles in a set of roles, but I can’t seem to get my head around this one.

I’ve got GetUsersInRole, Membership.GetAllUsers(), Linq,… but how?

Any feedback is greatly appreciated

Tommy

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T02:21:16+00:00Added an answer on May 19, 2026 at 2:21 am

    Here’s a Linq version, it returns a MembershipUserCollection just like the similar Membership methods (FindUsersByEmail, FindUsersByName). It’s not very pretty since it relies on the ForEach side effect:

        public static MembershipUserCollection FindUsersByRole(string[] roles)
        {
            MembershipUserCollection msc = new MembershipUserCollection();
    
            roles.Select(role => Roles.GetUsersInRole(role))
            .Aggregate((a, b) => a.Union(b).ToArray())
            .Distinct()
            .Select( user => Membership.GetUser(user))
            .ToList().ForEach( user => msc.Add(user));
    
            return msc;
        }
    

    Alternatively if a list of MembershipUser will do:

        public static List<MembershipUser> FindUsersByRole(string[] roles)
        {
            var userList = roles.Select(role => Roles.GetUsersInRole(role))
                                .Aggregate((a, b) => a.Union(b).ToArray())
                                .Distinct()
                                .Select( user => Membership.GetUser(user))
                                .ToList();
            return userList;
        }  
    

    And finally if you just need the user names you can skip one select:

        public static List<string> FindUsersByRole(string[] roles)
        {
            var userList = roles.Select(role => Roles.GetUsersInRole(role))
                                .Aggregate((a, b) => a.Union(b).ToArray())
                                .Distinct()
                                .ToList();
            return userList;
        }
    
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