Question

I want do delete all files with a specific extension (.xsl) whose names are not contained in another file. That is, if I have a file like

a.xsl
b.xsl
c.xsl

And a directory structure like

./a.xsl
./d.xsl
./folder1/b.xsl
./folder1/folder2/c.xsl
./folder1/folder2/e.xsl

I want to be able to delete d.xsl and e.xsl, but not a.xsl, b.xsl, or c.xsl. Target shell is BASH.

Answer 1

Something like this (Not tested):

for fn in $(find -type f -name '*.xsl')
do
  echo ${fn##*/} | grep -vf file1 >/dev/null && rm $fn
done

where file1 is the file containing the list of file entries.

${fn##*/} This removes everything till the last slash giving the filename alone. This is grepped against the file and if not resent, deleted.