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Home/ Questions/Q 6178129
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T00:24:32+00:00 2026-05-24T00:24:32+00:00

i want echo only value name no all. my array: $file_list[] = array( ‘name’

  • 0

i want echo only value name no all.

my array:

$file_list[] = array(
                            'name' => $CI->upload->file_name,
                            'file' => $CI->upload->upload_path.$CI->upload->file_name,
                            'size' => $CI->upload->file_size,
                            'ext' => $CI->upload->file_ext,
                            'image_type' => $imageVar->image_type,
                            'height' => $imageVar->height,
                            'width' => $imageVar->width
                            );
                }

my foreach:

foreach($upload_data as $file) {
    echo '<li><ul>';
    foreach ($file as $item => $value) {
        echo '<li>'.$item.': '.$value.'</li>';
    }
    echo '</ul></li>';
 } 

output now:

  • name: Chrysanthemum19.jpg
    file:
    D:/xampp/htdocs/Siran-mehdi/uploads/Chrysanthemum19.jpg
    size:
    858.78
    ext: .jpg
    image_type: jpeg
    height: 768
    width: 1024

  • name: Desert19.jpg
    file: D:/xampp/htdocs/Siran-mehdi/uploads/Desert19.jpg
    size: 826.11

    ext: .jpg
    image_type: jpeg
    height: 768
    width: 1024

i want this output:

Chrysanthemum19.jpg, Desert19.jpg

see you full class and Controller
class Multi_upload(libraries) CI_Controller

With respect

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T00:24:32+00:00Added an answer on May 24, 2026 at 12:24 am

    First you need to find the part of your loop that outputs the filename:

    echo '<li>'.$item.': '.$value.'</li>';
    

    You only want the value to be displayed when $item is equal to ‘name’. You can express that in code like this:

    $file['name']
    

    Then, eliminate all the parts of your code that do not contribute to the desired output. Your new code can look like this:

    $output = array();
    
    foreach($upload_data as $file) {
        $output[] = $file['name'];
    }
    
    echo implode( ',' $output );
    
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