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Home/ Questions/Q 875441
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T11:16:11+00:00 2026-05-15T11:16:11+00:00

I want functionality similar to the below: typedef int A; typedef int B; struct

  • 0

I want functionality similar to the below:

typedef int A;
typedef int B;


struct foo
{
  foo(A a) { /*specific to type A*/ }
  foo(B b) { /*specific to type B*/ }
};

I use the typedefs in my program to denote logically different usage of the same type. So, I would like to create object of type foo differently for different typedefs. I could compile this in g++, but msvc throws a fit saying that foo(A) is already defined when it sees the second definition foo(B). I thought of using a type list and the position of a type in the list to discriminate between the typedefs and tried using a boost::mpl::vector:

#include <boost/mpl/vector.hpp >
#include <boost/mpl/find.hpp>

typedef int A;
typedef int B;


struct foo
{
     typedef boost::mpl::vector<A, B> supported_types;

     foo(boost::mpl::find<supported_types, A>::type, A a) {}
     foo(boost::mpl::find<supported_types, B>::type, B b) {}
};

but unfortunately, find too discards my typedef and just returns iterator for A in both cases. I also thought about defining an enum and using it for each type

enum { TYPE_A, TYPE_B };
template <int i> struct int2type {};

and using this int2type and type B in the program. But this looks inelegant to me as it is prone to errors. I would like use a typelist and do this, so that it is clear what types would be supported.

Please let me know if there is a generic and extensible way of doing this.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T11:16:12+00:00Added an answer on May 15, 2026 at 11:16 am

    A boost strong typedef should do what you’re looking for.

    #include <boost/strong_typedef.hpp>
    
    BOOST_STRONG_TYPEDEF(int, A);
    BOOST_STRONG_TYPEDEF(int, B);
    
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