Question

I want in a table called week_year with following schema:

Week_year = {id, week, year}

To insert the weeks for each year, such that, for 2001 there is week 1, week 2, week 3, … , week 52, and then start over for year 2002 up until the year 2009.

I’ve tried different PHP scripts but can’t seem to be getting it right. I’ve tried different tables, one for year and one for week and then give each week a year_id, but that didn’t seem to be effective.

I’m hoping that someone can help me create, what I believe is a simple PHP loop(s) to generate these numbers and insert them into my MySQL database.

Added additional Information posted as an answer

I’ve tried this code, which is a endless loop of the year:

<?php

$year = 2001;
$week_start = 1;
$week_end = 52;

for ( $week_start = 1; $week_start <= 52; $week_start++ ) {

echo $week_start;
echo "<br />";
    for ($week_start = 1; $week_start <= 52; $year++) {
        echo $year;
        echo "<br />";
    }
}
?>

Answer 1

Do this in SQL, not PHP:

create table artificial_range( int id not null auto_increment, ci int);

insert into artificial_range(c1) values (1);

— NOW DOUBLE THE SIZE OF artificial_range

insert into artificial_range(c1) select c1 from artificial_range;

— repeat the above insert five more times;
— you now have 64 rows in artificial_range

-- now insert into week_year:
insert into week_year(week, year)
select a.id, b.id + 2000
from 
  artificial_range a,
  artificial_range b 
where a.id < 53 and b.id < 10;


-- or even better, just make week_year a view:
create view week_year as
select a.id as week, b.id + 2000 as year
from 
  artificial_range a,
  artificial_range b 
where a.id < 53 and b.id < 10;

One caveat: depending on what you mean by ‘week’, some years have 53 weeks.