Question

I want my application updates the screen information while the code is executing. I tried with this.LayoutRoot.UpdateLayout(); but it didn’t work and I don’t understand why. Can anyone help me?
The application receive a button propriety from a button clicked, then use that to a several things in a Model class, and then I want it show a message to the user. after that i want it continue executing more things (AI)… :S

public void showMsgFromModel(string player, string msg)
    {
        if(player!="")
            txNomeMsg.Text = player + ":";
        else
            txNomeMsg.Text = player;

        txMsg.Text = msg;
        this.LayoutRoot.UpdateLayout();
        System.Threading.Thread.Sleep(1500);
    }

Answer 1

You’re trying to do some processing from the UI thread, which is therefore unable to update the interface.

Use a background worker to execute long-running tasks, and use the dispatcher when you need to update the UI:

var worker = new BackgroundWorker();

worker.DoWork += (s, e) =>
{
    Thread.Sleep(1500); // Some processing

    Dispatcher.BeginInvoke(() => txMsg.Text = "Hello"); // Update the UI

    Thread.Sleep(1500); // More processing
};

worker.RunWorkerAsync();