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Home/ Questions/Q 336805
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T10:16:36+00:00 2026-05-12T10:16:36+00:00

i want something like this: SELECT DISTINCT ID from copies WHERE timestamp < 1229444506

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i want something like this:

SELECT DISTINCT ID from copies WHERE timestamp < 1229444506 ORDER BY CID 

the problem is that this one only return ID and i need CID and other columns in the table.

It may be that this is totally wrong for other reason aswell, so i will explain what i need.

I have a table that “record” every row-change in my maintable. This so in the future i will be able to go back in time and see how the main table looked like a certain date in time.

So what i need is a query that ORDER all rows BY CID, WHERE timestamp < 1229444506, AND then DISCTINCT them by ID.

I want to the query to return the first row by ID, when ordered by CID newest first.

Ive tried to get this working with different methods but no luck.
Any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-05-12T10:16:37+00:00Added an answer on May 12, 2026 at 10:16 am

    I am not sure if I got it correctly, but what about creating a subquery that will just select the columns? You wrote:
    “I want to the query to return the first row by ID, when ordered by CID newest first.”

    So, let’s make a subquery:

    SELECT id, max(cid) as maxcid FROM copies WHERE timestamp < XX group by id
    

    This will give you the relationship id <=> the CID you want. And now join it:

    SELECT copies.* FROM copies, (SELECT id, max(cid) as maxcid FROM copies WHERE timestamp < xxx group by id) x  
    WHERE copies.id=x.id AND copies.cid=x.maxcid;
    
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