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Home/ Questions/Q 978081
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Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T04:00:24+00:00 2026-05-16T04:00:24+00:00

I want that when mouse is over an image, an event should be triggered

  • 0

I want that when mouse is over an image, an event should be triggered ONCE, and it should be triggered again only after mouse is out of that image and back again, and also at least 2 seconds passed.

If I leave my mouse over the image,it gets called like every milisecond,and by the logic of my function once you hover on the variable ‘canhover’ becomes 0 until you move mouse out

This code seems to have a bug and I cant see it. I need a new pair of eyes, but the algorithm is kinda logical

Working code :

<script type="text/javascript">
var timeok = 1;
function redotimeok() {
    timeok = 1;
}
//
function onmenter()
{
if (timeok == 1) 
    {
  enter();
  timeok = 0;
    }
}
//
function onmleave()
{
  setTimeout(redotimeok, 2000);
  leave();
}
//

$('#cashrefresh').hover(onmenter,onmleave);

function enter(){
  $("#showname").load('./includes/do_name.inc.php');
  $("#cashrefresh").attr("src","images/reficonani.gif");
}

function leave(){
  $("#cashrefresh").attr("src","images/reficon.png");
}
</script>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T04:00:25+00:00Added an answer on May 16, 2026 at 4:00 am

    I don’t know if this will solve your entire problem (since we don’t have a detailed description of what it is), but instead of:

    $('#cashrefresh').hover(onmenter(),onmleave());
    

    try:

    $('#cashrefresh').hover(onmenter,onmleave);
    

    And the same thing here:

    setTimeout(redotimeok, 2000); // just the function name
    

    Also, I don’t see where you ever set timeok to zero. Do you mean to set timeok = 0 in onmenter()?

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