Question

I want the data returned from an ajax post to be put into a javascript variable where I can then run an if statement checking whether that variable is equal to true. However, Firebug is telling me the variable verify is not defined. How do I write the function within the ajax post to set the data to verify correctly? Code is below.

$.post('ajax_file.php', 
{
user_id: user_id,    
band_term: band_term
}, function (data) {
var verify = data;              

if (verify == 'true') 

   {

   $('#request_form').hide();                  

   $('#where_to_go').hide();                            

   $('#change_form').show();                                    

}});

The ajax file returns true on success and false on failure.

if (mysql_query($sql) == true)

{ echo 'true';} else {echo 'false';}

Firebug shows me that the ajax file is returning with the string true, so I know the ajax file is working.

Answer 1

The issue is on a few places.
First, how you output data on you .php file. You should be returning JSON and accepting JSON on you ajax request. Look at this example:

<?php
    $variable = array("stat" => true, "data" => array(10, 10));
    print_r(JSON_Encode($variable));
?>

That will output this:

{"stat":true,"data":[10,10]}

Then on yout JS you’d do:

$.post('ajax_file.php', {
   user_id: user_id,    
   band_term: band_term
}, function (data) {
   //Data is the whole object that was on the response. Since it's a JSON string, you need to parse it back to an object.

   data = JSON.parse(data);

   if (data.stat === true){
      $('#request_form').hide();                  
      $('#where_to_go').hide();                            
      $('#change_form').show();                                    
   }
});