Question

I want the Logout link to carry out a process located in HomeController and not to display a new View. How do I go about structuring this?

Controller method:

public ActionResult LogoutProcess()
    {
        previousLoggedIn = WebSecurity.CurrentUserName;
        WebSecurity.Logout();
        return RedirectToAction("Logout", "Home");
    }

    public ActionResult Logout(HomeModels.LogoutModel model)
    {
        model.PreviouslyLoggedInUsername = previousLoggedIn;
        return View(model);
    }

View:

<a href = "@Url.Action("LogoutProcess", "Home")">Logout</a>

Answer 1

You can use the standard link, targeting that action

@Url.Action("LogoutProcess", "Home")

The “trick” is in Redirection to some other View at the end of your LogoutProcess() action:

public ActionResult LogoutProcess()
{
    // TempData to transfer user name      
    TempData["previousLoggedIn"] = WebSecurity.CurrentUserName;
    WebSecurity.Logout();
    return RedirectToAction("Logout", "Home");
}

public ActionResult Logout(HomeModels.LogoutModel model)
{
    // fill model from TempData
    model.PreviouslyLoggedInUsername = TempData["previousLoggedIn"];
    return View(model);
}

The CurrentUserName is passed to other action via TempData