Question

I want the next ‘a’ element of current ‘a’. When current is 2,3,4 I catch 3,4,5 with a $(‘a.current’).nextAll(‘a’) but when current is 5 i can’t catch the next ‘a’.
If someones has the solution…

<div id="slides">
    <ul>
     <li>
        <a href="" class='current'>2</a>
        <a href="" >3</a>
        <a href="" >4</a>
        <a href="" >5</a>
     </li>
      <li>
        <a href="" >6</a>
        <a href="" >7</a>
        <a href="" >8</a>
        <a href="" >9</a>
     </li>
    </ul>
</div>

Answer 1

var curr = $('a.current'),            // get the current
    a = curr.closest('ul').find('a'), // get all the "a" elements
    idx = a.index(curr),              // get the index of the current among all
    nextall = a.slice(idx + 1);       // slice those greater than the current

live demo: http://jsfiddle.net/eaXdc/

---

If you only wanted the next one, change this:

a.slice(idx + 1);

to this:

a.eq(idx + 1);