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Home/ Questions/Q 6376117
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:42:13+00:00 2026-05-25T01:42:13+00:00

I want the offsetof() the param line in mystruct1 . I’ve tried offsetof(struct mystruct1,

  • 0

I want the offsetof() the param line in mystruct1. I’ve tried

offsetof(struct mystruct1, rec.structPtr1.u_line.line) 

and also

offsetof(struct mystruct1, line)  

but neither works.

union {
    struct mystruct1 structPtr1;
    struct mystruct2 structPtr2;
} rec;

typedef struct mystruct1 {
    union {
        struct {
            short len;
            char buf[2];
        } line;

        struct {
            short len;
        } logo;

    } u_line;
};
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:42:14+00:00Added an answer on May 25, 2026 at 1:42 am

    The offsetof() macro takes two arguments. The C99 standard says (in §7.17 <stddef.h>):

    offsetof(type, member-designator)
    

    which expands to an integer constant expression that has type size_t, the value of
    which is the offset in bytes, to the structure member (designated by member-designator),
    from the beginning of its structure (designated by type). The type and member designator
    shall be such that given

    static type t;
    

    then the expression &(t.member-designator) evaluates to an address constant.

    So, you need to write:

    offsetof(struct mystruct1, u_line.line);
    

    However, we can observe that the answer will be zero since mystruct1 contains a union as the first member (and only), and the line part of it is one element of the union, so it will be at offset 0.

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