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Home/ Questions/Q 1074725
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:10:11+00:00 2026-05-16T21:10:11+00:00

I want the text REPLACEME to be replaced with my StringBuffer symbols. When I

  • 0

I want the text “REPLACEME” to be replaced with my StringBuffer symbols. When I print symbols, it is a valid string. When I print my query, it still has the text REPLACEME instead of symbols. Why?

private String buildQuery(){
    String query = "http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.quotes%20where%20symbol%20in%20(REPLACEME)&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys&callback=";

    deserializeQuotes();

    StringBuffer symbols = new StringBuffer();
    for(int i = 0; i < quotes.size();i++){
        if(i == (quotes.size()-1))
            symbols.append("%22" + quotes.get(i).getSymbol() + "%22%"); //end with a quote
        else
            symbols.append("%22" + quotes.get(i).getSymbol() + "%22%2C");
    }

    System.out.println("***SYMBOLS***" + symbols.toString());
    query.replaceAll("REPLACEME", symbols.toString());

    return query;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:10:12+00:00Added an answer on May 16, 2026 at 9:10 pm

    Change

    query.replaceAll("REPLACEME", symbols.toString());
    

    to:

    query = query.replaceAll("REPLACEME", symbols.toString());
    

    Strings in Java are designed to be immutable.
    That is why replaceAll() can’t replace the characters in the current string, so it must return a new string with the characters replaced.


    Also if you want to simply replace literals and don’t need regex syntax support use replace instead of replaceAll (regex syntax support is only difference between these two methods). It is safer in case you would want to replace literals which can contain regex metacharacters like *, +, [, ] and others.

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