Question

I want the variable “minne” to be counted upwards once ever time I run the function “multi” and then print it back on the screen in the main function.
This doesnt happen though, it is stuck on telling me I used the function “0” times over and over again. Why is that?

//Multi

#include <iostream>


//Deklarerar variablar
int a,b,x, minne;

//Deklarerar funktioner
int multi(int a, int b);

int main(void)
{
  using std::cout;
  using std::cin; 

  while(1 < 2)
  {
  cout << "Ge mig ett nummer som du vill multiplicera:\n"; 
  cin >> a;
  cout << "\n Och ett till tack: \n";
  cin >> b;

  multi(a,b);

  cout << "\n Summan av dessa tal är: " << x << "\n";
  cout << "You have called the function: " << minne << " times.\n";
  }

  return 0;
}

int multi(int a, int b)
{
  x = a * b;

  int minne = minne + 1;

  return x, minne;
}

Answer 1

You’re hiding the global minne with your local int minne – get rid of the int and just write minne = minne + 1, or even just ++minne. Also, you don’t need to return anything from the function as you’re not using the result.