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Home/ Questions/Q 8263115
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T03:59:19+00:00 2026-06-08T03:59:19+00:00

I want to Access php web service using ajax jquery This is my code:-

  • 0

I want to Access php web service using ajax jquery
This is my code:-

$.ajax({
        type: "POST",
    url:'http://localhost:8080/onestatus/webservice/login?email=kk@kk.com&password=123456',
         cache: false,
          dataType: "json",
          success: onSuccess
        });

function onSuccess(data) {
       // var data = data.d;
        var result = $.parseJSON(data);
        var arrayObject = new Array();
        for (var i = 0; i < result.user.length; i++) {
           // $('#resultLog').append('<li>' + result.user[i].user_id + '</li>');
         }
    }

when i use dataType: “json” then i am getting request.status=0 noting getting in responce

and when use dataType: “jsonp” getting error in firbug

SyntaxError: invalid label
[Break On This Error]
{“user”:[{“response”:”success”,”user_id”:”28″,”session_id”:123456}]}

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  1. Editorial Team
    Editorial Team
    2026-06-08T03:59:20+00:00Added an answer on June 8, 2026 at 3:59 am

    Two cases:

    1. The URL http://localhost:8080/onestatus/webservice/login is placed on a domain different from the requesting domain(note: the port must match too) : you will not be able to request a JSON, it’s restricted by SOP
    2. you may request a JSONP from a different domain, but the received response is not JSONP

    So what you can do:
    When the webservice is under your control, change the response to proper JSONP. Otherwise you can’t do anything.

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