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Home/ Questions/Q 8737407
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T10:30:53+00:00 2026-06-13T10:30:53+00:00

i want to add a conditional statement to my layout that tests: the controller

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i want to add a conditional statement to my layout that tests:

  1. the controller param in the url
  2. the existence of a zend_auth()

what’s the best way to achieve that? i have tried testing the $this->_getParam('controller') in the layout but got an error. i could just set that variable in all the controllers but that seems kind of dumb. how to best set a variable that i could use later from the layout with some conditional logic? or should i instead add my conditional logic that is inside a view helper and then loaded into the layout?

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  1. Editorial Team
    Editorial Team
    2026-06-13T10:30:54+00:00Added an answer on June 13, 2026 at 10:30 am

    Edit The controller shouldn’t be a URL parameter, unless you are doing some very strange routing. If you were getting a GET (or POST) variable, you would use ->getParam() on the request object, Zend_Controller_Front::getInstance()->getRequest(), as used below. But the controller is a separate property of that request object.

    This is the auth part:

    $loggedIn = Zend_Auth::getInstance()->hasIdentity();
    

    This is the controller part:

    $controller = Zend_Controller_Front::getInstance()->getRequest()->controller;
    
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