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Home/ Questions/Q 499231
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:57:52+00:00 2026-05-13T05:57:52+00:00

I want to add a operator override to perform assignments /__set__s inline. Template :-

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I want to add a operator override to perform assignments/__set__s inline.

Template :-

class CBase {
    public :
        static void SetupVmeInterface(CVmeInterface *in);

    protected :
        static CVmeInterface *pVmeInterface;
};


template <class T> class TCVmeAccess : public CBase {
    public:
        TCVmeAccess(int address);

        T get()
        {
            unsigned long temp = pVmeInterface->ReadAddress(Address);
            T ret = *reinterpret_cast<T*>(&temp);
            return ret;
        };

        T *operator->();
        unsigned long asLong();

        bool set(T data)
        {
            unsigned long write_data = *reinterpret_cast<unsigned long*>(&data);
            return pVmeInterface->WriteAddress(Address, write_data);
        };

        // void operator->(T);
        void operator=(T data)
        { set(data); }

    private :
        int Address;
};

A struct that will be used in the template :-

typedef struct
{
    int a: 1; // 0
    int b: 1; // 1
    int c: 1; // 2
    int d: 1; // 3
    int NotUsed : 28; // 31-4
} _HVPSUControl;

Code body :-

TCVmeAccess<_HVPSUControl> HVPSUControl(constHVPSUControlBlock);
_HVPSUControl hvpsu = HVPSUControl.get(); // Yep, good, but not as nice as...
int a = HVPSUControl2.get().OperationalRequestPort; // yep, also good, but...
int b = HVPSUControl->a; // works, and is all go so far

HVPSUControl.set(hvpsu); // works, but need _HVPSUControl type
HVPSUControl = hvpsu;    // also works, as operator = is used, but still need type

// this line does not work!
// as the = assignment is redirected into a copy of the struct, not the template
HVPSUControl->a = 1; // this line

So, is there a way to get this line above to work?

Edit:
As in, I want “this line” to perform as a “set” as does in the template class.

Edit:
1. Assign a value directly in-line to a member of the struct that the template is formed
of.
2. Cause that assignment to go though a template accessor.

So that I dont have to do this on assignments :-

// HVPSUControl is predefined and used many times.
_HVPSUControl hvpsu;
hvpsu.a = 1;
HVPSUControl.set(hvpsu);

I want to do

HVPSUControl.a = 1; // or 
HVPSUControl->a = 1; // or ?

As gets work on line :

if (HVPSUControl->a)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:57:52+00:00Added an answer on May 13, 2026 at 5:57 am

    Instead of overwriting the “->” and the “=” operator, you could derive from the template struct.

    template <class T> class TCVmeAccess : public CBase, public T {
        public:
            TCVmeAccess(int address);
    
            T get();
            // T *operator->();
            unsigned long asLong();
    
            bool set(T);
            // void operator->(T);
            // void operator=(T);
    
        private :
            int Address;
    };
    
    HVPSUControl.a = 1; // and use this for setting a bitfield.
    

    Edit: If you want to use an custom assignment operator, you should declare it in HVPSUControl, or a even a base class of it, if you have more of this control-like structures.

    struct _HVPSUControl
    {
        int a: 1; // 0
        int b: 1; // 1
        int c: 1; // 2
        int d: 1; // 3
        int NotUsed : 28; // 31-4
        void operator = (int x);
    };
    

    or

    struct _HVPSUBase {
        void operator = (int x);
    }
    struct _HVPSUControl: public _HVPSUBase
    {
        int a: 1; // 0
        int b: 1; // 1
        int c: 1; // 2
        int d: 1; // 3
        int NotUsed : 28; // 31-4
    };
    
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