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Home/ Questions/Q 6576351
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:30:05+00:00 2026-05-25T15:30:05+00:00

I want to add to {status:true} so that the string looks like {status:true} .

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I want to add "" to {"status":true} so that the string looks like "{"status":"true"}". How can I insert characters to a string at specific locations?

I tried strncat(), but wasn’t able to get the desired result. I read that you need to create your own function for that. Can anyone show me an example?

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  1. Editorial Team
    Editorial Team
    2026-05-25T15:30:06+00:00Added an answer on May 25, 2026 at 3:30 pm

    Yes, you will need to write your own function for that.

    Note that a string in C is a char[], i.e. an array of characters, and is of fixed size.

    What you can do is, create a new string that serves as the result, copy the first part of the subject string into it, append the string that goes in the middle, and append the second half of the subject string.

    The code goes something like,

    // inserts into subject[] at position pos
    void append(char subject[], const char insert[], int pos) {
        char buf[100] = {}; // 100 so that it's big enough. fill with zeros
        // or you could use malloc() to allocate sufficient space
        // e.g. char *buf = (char*)malloc(strlen(subject) + strlen(insert) + 2);
        // to fill with zeros: memset(buf, 0, 100);
    
        strncpy(buf, subject, pos); // copy at most first pos characters
        int len = strlen(buf);
        strcpy(buf+len, insert); // copy all of insert[] at the end
        len += strlen(insert);  // increase the length by length of insert[]
        strcpy(buf+len, subject+pos); // copy the rest
    
        strcpy(subject, buf);   // copy it back to subject
        // Note that subject[] must be big enough, or else segfault.
        // deallocate buf[] here, if used malloc()
        // e.g. free(buf);
    }
    

    Working example here

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