Question

I want to AND or OR all the elements in an array, but with some control, as shown via the hash element selection. Here is the behavior that I wish to achieve:

a = [{:a => true}­, {:a => false­}]
a.and_map{ |hash_element| hash_element[:a] }
#=> false
a.or_map{ |hash_element| hash_element[:a] }
#=> true

Is there a slick, clean way to do this in Ruby?

Answer 1

You can use all? and any? for that:

a = [{:a => true}, {:a => false }]
a.any? { |hash_element| hash_element[:a] }
#=> true
a.all? { |hash_element| hash_element[:a] }
#=> false