Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7857081
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 2, 20262026-06-02T20:55:17+00:00 2026-06-02T20:55:17+00:00

I want to append the name of the file which has been uploaded using

  • 0

I want to append the name of the file which has been uploaded using the $_POST method to post the $_FILES['fileImage']['name'] from the php script. Problem is that after the file has been uploaded, I don’t see the filename appended, it just shows a blank. Why is it not appending the file’s name after succesful upload of the file?

If anyone could provide a coded example then it would be very helpful.

Below is Javascript code:

   <?php
    session_start();

    $output = array();
    if(isset($_POST['fileImage'])){
        $idx = count($_POST['fileImage']) -1 ;
        $output[] = isset($_POST['fileImage'][$idx]) ?
            $_POST['fileImage'][$idx]['name'] : "";
    }

    ?>

     <script>   


    function stopImageUpload(success) {
        var imageNameArray = <?php echo  json_encode($output); ?>;
        var result = '';

        if (success == 1) {
            result = '<span class="msg">The file was uploaded successfully!</span><br/><br/>';
            for (var i = 0; i < imageNameArray.length; i++) {
                $('.listImage').append(imageNameArray[i] + '<br/>');
            }
        }
        else {
            result = '<span class="emsg">There was an error during file upload!</span><br/><br/>';
        }

        return true;
    }

</script>

Below is the php script which uploads the file and this script is on a seperate age from the Javascript function:

 <?php
session_start();

$result = 0;
$errors = array ();
$dirImage = "ImageFiles/";

if (isset ( $_FILES ['fileImage'] ) &&
    $_FILES ["fileImage"] ["error"] == UPLOAD_ERR_OK) {

    $fileName = $_FILES ['fileImage'] ['name'];

    $fileExt = pathinfo ( $fileName, PATHINFO_EXTENSION );
    $fileExt = strtolower ( $fileExt );

    $fileDst = $dirImage . DIRECTORY_SEPARATOR . $fileName;

    if (count ( $errors ) == 0) {
        if (move_uploaded_file ( $fileTemp, $fileDst )) {
            $result = 1;
        }
    }
}

$_SESSION ['fileImage'][] = array('name' => $_FILES ['fileImage']['name']);
?>
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-02T20:55:18+00:00Added an answer on June 2, 2026 at 8:55 pm

    Because you’re looking in $_POST for a variable which is in $_SESSION. Try changing it to:

    $output = array();
    if(isset($_SESSION['fileImage'])){
        $idx = count($_SESSION['fileImage']) -1 ;
        $output[] = isset($_SESSION['fileImage'][$idx]) ?
            $_SESSION['fileImage'][$idx]['name'] : "";
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a binary file to which I want to append a chunk of
I m getting json reponse from php file [{med_name:Test,COUNT(e_u.med_id):3}] using jquery ajax which I
I want to search a file in the current directory from which the batch
I want to append a div inside a div which have many divs inside
I want to append a <br /> to a particular class. Using the :after
If I want to append the contents of a src file into the end
I want to load an XML file which is in D: drive. This is
I want to append the last motify date to a FileName which will be
I am using itertools.groupby to parse a short tab-delimited textfile. the text file has
I'm using paperclip with my rails 3 app. I want to append a random

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.