Question

I want to be able to loop over a list and return a single row where all the list elements have matched.

e.g.

lest say my list of id’s is 1,2,3 I want to write an SQL statment that will do the following (without breaking).

SELECT id1
FROM TBL
WHERE 0=0
AND id2 = 1
AND id2 = 2
AND id2 = 3

Is this possible?

Thanks in advance

Answer 1

Do you mean that you want all id1 records for which there is a matching id2=1 and a matching id2=2 and a matching id2=3?

WITH tbl As
(
SELECT 1 AS id1, 1 AS id2 UNION ALL
SELECT 1 AS id1, 2 AS id2 UNION ALL
SELECT 1 AS id1, 3 AS id2 UNION ALL
SELECT 1 AS id1, 4 AS id2 UNION ALL
SELECT 2 AS id1, 1 AS id2 UNION ALL
SELECT 2 AS id1, 2 AS id2 UNION ALL
SELECT 3 AS id1, 1 AS id2 UNION ALL
SELECT 3 AS id1, 2 AS id2 UNION ALL
SELECT 3 AS id1, 3 AS id2
)
SELECT id1 
FROM tbl 
WHERE id2 IN (1,2,3)
GROUP BY id1
HAVING COUNT(DISTINCT id2) = 3

Returns

id1
-----------
1
3

Is that what you need?