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Home/ Questions/Q 3400988
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T04:57:37+00:00 2026-05-18T04:57:37+00:00

I want to be able to return true/false depending on an IP being in

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I want to be able to return true/false depending on an IP being in range of two other IPs.

For instance:

ip 192.200.3.0

range from 192.200.0.0

range to 192.255.0.0

should result to true.

Other examples:

assert 192.200.1.0 == true
assert 192.199.1.1 == false
assert 197.200.1.0 == false
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T04:57:37+00:00Added an answer on May 18, 2026 at 4:57 am

    The easiest way to check the range is probably to convert the IP addresses to 32-bit integers and then just compare the integers.

    public class Example {
        public static long ipToLong(InetAddress ip) {
            byte[] octets = ip.getAddress();
            long result = 0;
            for (byte octet : octets) {
                result <<= 8;
                result |= octet & 0xff;
            }
            return result;
        }
    
        public static void main(String[] args) throws UnknownHostException {
            long ipLo = ipToLong(InetAddress.getByName("192.200.0.0"));
            long ipHi = ipToLong(InetAddress.getByName("192.255.0.0"));
            long ipToTest = ipToLong(InetAddress.getByName("192.200.3.0"));
    
            System.out.println(ipToTest >= ipLo && ipToTest <= ipHi);
        }
    }
    

    Rather than InetAddress.getByName(), you may want to look at the Guava library which has an InetAddresses helper class that avoids the possibility of DNS lookups.

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