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Home/ Questions/Q 8609173
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T03:48:55+00:00 2026-06-12T03:48:55+00:00

I want to better understand the effects JavaScript closures have on memory: function fee(arg){

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I want to better understand the effects JavaScript closures have on memory:

function fee(arg){

  function figh(){
    //some code
     fum(passOnSomeARG)
  }     

  function fo(y){
    //some calculations with y
  }

  function fum(x){
    //some code
     fo(x)
  }

  figh()
}

In the above example are the inner functions re-read into memory every time “fee()” is called? if so is this efficient? If not then what is happening?

side note: fee() may be called a lot of times in succession (either a loop or a mouse event onmousemove)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T03:48:56+00:00Added an answer on June 12, 2026 at 3:48 am

    I think so, yes. It would be more efficient to do this:

    (function() {
        var figh = function() {
            // some code
            fum(passOnSomeARG);
        };
        var fo = function(y) {
            // some calculations with y
        };
        var fum = function(x) {
            // some code
            fo(x);
        };
        window.fee = function(arg) {
            figh();
        };
    })();
    
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