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Home/ Questions/Q 6218511
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T07:37:22+00:00 2026-05-24T07:37:22+00:00

I want to build an build a function that does return me an already

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I want to build an build a function that does return me an already existing instance of a form.

fx = getForm(Form1);

here i get the error ‘FensterTest.Form1’ is a ‘type’ but is used like a ‘variable’
So i need some casting, but i have no idea in what i need to cast.

private Form getForm(Form f)
{
  foreach (Form a in Application.OpenForms)
  {
    if (a is f)
    {
      f fx = (f)a;
      return fx;
    }
  }
  return null;
}

and wherever i use “f” i get a “type or namespace name ‘f’ not found”

“f fx = (f)a;” was formerly “Form1 fx = (Form1)a;” and that worked quite well, but since i do also need to use Form2 Form3, …

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T07:37:23+00:00Added an answer on May 24, 2026 at 7:37 am

    You probably want to find the Form from the OpenForms collection, that is of a specified type. So you need to pass the type in – you can either pass in a Type object, or you can make the method generic so you can pass in a type parameter. Sending in a type parameter has the advantage that you can be type safe (returning the concrete type that you searched for in case you need it). Here is a generic solution:

    private TForm getForm<TForm>()
        where TForm : Form
    {
        return (TForm)Application.OpenForms.OfType<TForm>().FirstOrDefault();
    }
    

    Note, OfType and FirstOrDefault is a LINQ extension methods, make sure you import System.Linq.
    Use the method above like this:

    Form f = getForm<Form1>();
    
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