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Home/ Questions/Q 8812809
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T03:41:22+00:00 2026-06-14T03:41:22+00:00

I want to check a php variable in javascript and create an Array accordingly.

  • 0

I want to check a php variable in javascript and create an Array accordingly.

I tried this, but it’s not working:

<script language="Javascript" type="text/javascript">
            var phpvar1_large = <?php echo $var1_large ?>; 
            var phpvar2_large = <?php echo $var2_large ?>; 
            var phpvar3_large = <?php echo $var3_large ?>; 
            var phpvar4_large = <?php echo $var4_large ?>; 

            if(!phpvar1_large){
            var imgArray = new Array(
                '<?=$main_img; ?>'
                );
            }else if(!phpvar2_large){
                var imgArray = new Array(
                '<?=$main_img; ?>',
                '<?=$var1_large; ?>'
                );
            }else if(!phpvar3_large){
            var imgArray = new Array(
                '<?=$main_img; ?>',
                '<?=$var1_large; ?>',
                '<?=$var2_large; ?>',
                '<?=$var3_large; ?>'
                );
            }else if(!phpvar4_large){
                var imgArray = new Array(
                '<?=$main_img; ?>',
                '<?=$var1_large; ?>',
                '<?=$var2_large; ?>',
                '<?=$var3_large; ?>'
                );
            }else if(phpvar4_large){
            var imgArray = new Array(
                '<?=$main_img; ?>',
                '<?=$var1_large; ?>',
                '<?=$var2_large; ?>',
                '<?=$var3_large; ?>',
                '<?=$var4_large; ?>'
            );
            }
</script>

However, if I don’t use an if-statement, the array is created correctly:

<script language="Javascript" type="text/javascript">
            var imgArray = new Array(
                '<?=$main_img; ?>',
                '<?=$var1_large; ?>',
                '<?=$var2_large; ?>',
                '<?=$var3_large; ?>',
                '<?=$var4_large; ?>'
            );
</script>

I appreciate your help very much!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T03:41:23+00:00Added an answer on June 14, 2026 at 3:41 am

    I’m pretty sure your problem is that the boolean values you are writing via php are not being interpreted as boolean but strings, that is why it is always evalued as false.

    you should write var phpvar1_large = <?php echo json_encode($var1_large); ?>;

    You are welcome!

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