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Home/ Questions/Q 8662307
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T16:42:13+00:00 2026-06-12T16:42:13+00:00

I want to check if foo exists in the array named Array , but

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I want to check if "foo" exists in the array named "Array", but $.inArray always returns -1. Why does it return -1 and how do I solve this?

Here is my code in a jsFiddle:

var Array = []
Array.push({'test':'fuu','url':'sdfsdfsdf'});
Array.push({'test':'qsgbfdsbgsdfbgsfdgb','url':'sdfssffbgsfdbgdfsdf'});
if($.inArray('fuu',Array) != -1) alert('present');
else alert('absent');
alert($.inArray('fuu',Array));
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T16:42:15+00:00Added an answer on June 12, 2026 at 4:42 pm

    'fuu' is not actually in the array, it’s a value of an object inside of the array. I’m afraid that you need a more complex check. I would also not use Array as the variable name as that’s the name of the Array object, but apparently it’s not a reserved word? not sure.

    var arr = [];
    ...
    var found = false;
    $.each(arr, function () {
       if (this.test === 'fuu') {
          found = true;
          return false;
       }
    });
    if (found) alert('present');
    
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