Question

I want to check if there are two or more values ​​in a string, regardless of their positions within said string. For example, if I want a condition of “OR” in regex, I would do so:

/(a|b)/.test("a") // true

But what I need is an “AND”; something like this:

/(a&b)/.test("a") // false
/(a&b)/.test("b") // false
/(a&b)/.test("a b") // true
/(b&a)/.test("a b") // true
/(a&b&c)/.test("a b") // false
/(a&b&c)/.test("a c b") // true

Obviously this syntax is not correct…

These values a, b, c, etc. are pulled from an array. I’ve tried using a combination of eval() and indexOf(a) !== -1 && indexOf(b) !== -1 but that was too slow, which is why I’m turning to regexes.

Answer 1

Since you’re matching fixed strings, you could just use:

function matchAll(str, arr)
{
  for (var i=0; i<arr.length; ++i) {
    if (str.indexOf(arr[i]) === -1) {
      return false;
    }
  }
  return true;
}

matchAll('a', ['a']); // true
matchAll('a', ['a', 'b']); // false
matchAll('a b', ['a', 'b']); // true
matchAll('a b c', ['a', 'b']); // true
matchAll('a b', ['a', 'b', 'c']); // false
matchAll('a c b', ['a', 'b', 'c']); // true
matchAll('c a b', ['a', 'b', 'c']); // true

If you’re looking for fixed strings, .indexOf() will be faster than regexes.